JEE Main 2026 Mole Concept and Stoichiometry Practice Set with Solutions

JEE Main 2026 Mole Concept and Stoichiometry questions are usually numerical and involve unit conversion, logic and applying concepts. If you master molar mass calculations, chemical equations and formulas, then your overall performance can improve. Practising the important questions will boost your JEE Main 2026 exam preparation. This article provides practice sets with solutions for JEE Main 2026 Mole Concept and Stoichiometry. The test-takers are advised to start answering the questions on their own and then check the solutions if stuck.

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JEE Main 2026 Mole Concept and Stoichiometry Practice Set with Solutions

The JEE Main 2026 applicants can improve their Chemistry preparation by solving the Mole Concept and Stoichiometry practice problems. The Mole Concept and Stoichiometry is a scoring topic and at least 1 question will be asked from this section.

Q1. How many moles are there in 88 g of carbon dioxide (CO₂)? (C = 12.011, O = 15.999)

Solution:

Molar mass M(CO₂) = 12.011 + 2×15.999 = 12.011 + 31.998 = 44.009 g·mol-1

Moles = mass / M = 88 ÷ 44.009 ≈ 2.000

Answer: 2.00 mol

Q2. How many molecules are present in 0.5 mol of H₂O?

Solution:

1 mol = 6.02214076 × 1023 molecules. So molecules = 0.5 × 6.02214076 × 1023 = 3.01107038 × 1023

Answer: 3.011 × 1023 molecules

Q3. A compound contains 40% C, 6.7% H and 53.3% O by mass. Find its empirical formula.

Solution:

Assume 100 g → C: 40 g, H: 6.7 g, O: 53.3 g. Moles: C = 40 ÷ 12.011 ≈ 3.331; H = 6.7 ÷ 1.008 ≈ 6.646; O = 53.3 ÷ 15.999 ≈ 3.332. Divide by smallest ≈3.331: C: 1.000, H: 1.998 ≈2, O: 1.000. Empirical formula CH₂O.

Answer: CH₂O

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JEE Main 2026 Mole Concept and Stoichiometry Practice Questions PDF

Solving the JEE Main 2026 Mole Concept and Stoichiometry questions will give the students the confidence to answer the questions asked in the exam. We have provided some important JEE Main sample papers on Mole Concept and Stoichiometry with solutions in the PDF below.

JEE Main 2026 Mole Concept and Stoichiometry Preparation Tips

The Mole Concept and Stoichiometry part has 3.3% of the total weightage of JEE Mains. So, if you want to score well in this section, follow the JEE Main 2026 preparation tips provided below that will help you answer the question correctly.

• Make sure your fundamentals are clear in topics like atomic and molar mass, Avogadro’s number, mole–mass–volume conversions and Stoichiometric coefficients.

• You can memorise important formulas on the number of moles, molarity, normality, mole fraction, empirical & molecular formula relations, conversions etc.

• Students make mistakes during converting units, so make sure you check ml ↔ L conversions, g ↔ mol conversions and STP volume (22.4 L) usage before calculating.

• Try analysing your mistakes, keep an error book and review all the mistakes before you take the final exam.

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Mole Concept and Stoichiometry are an important part of the Chemistry syllabus. So, if your fundamentals are strong, you can score full marks from this section in JEE Mains 2026. Solve the JEE Main Chemistry practice qeuestions with solutions to strengthen your grip over Mole Concept and Stoichiometry questions.

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